(b)Diborane, B₂H6, can be prepared by the following reaction:
NaBH4 (s) + BF3(g) B₂Hs(g) + NaBF4(s)

i. Balance the equation

ii. How many moles of NaBH, react with 1.299 mol of BF3?

iii.How many moles of B₂H, can be obtained from 0.893 mol of NaBH₂?

iv. If 1.987 mol of B₂H, is obtained, how many moles of NaBF, are produced?
[7 marks]
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