Can someone please help me solve this and walk me through the steps to help my understanding?
A precipitation reaction occurs when 791 mL of 0.765 M Pb(NO3)2 reacts with 549 mL of 0.861 M KI, as shown by the following equation.
Pb(NO3)2(aq)+2KI(aq)⟶PbI2(s)+2KNO3(aq)
Calculate the theoretical yield of PbI2 from the reaction.
Calculate the percent yield of PbI2 if 88.6 g of PbI2 are formed experimentally.
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