Molar masses:

Phosphoric acid = 98 g/mol

Sodium sulfate = 142.05 g/mol

Sodium phosphate = 163.94 g/mol

Sulfuric acid = 98.09 g/mol

1a. If 1.08g of sodium sulfate reacts with an excess of phosphoric acid, what mass of sulfuric acid is theoretically produced?

The known substance is , the value given is and the molar mass conversion is Response area. The unknown substance is Response area and the mol to mol ratio of unknown to known is Response area. The molar mass conversion of the unknown is Response area and the final answer in correct sigfigs is Response area for the mass of sulfuric acid produced.

1b. Calculate the % yield if the mass of sulfuric acid produced experimentally in the lab is 0.726g Response area.