Dennis thought of a number. He adds 0.5 to that number and then multiplies the new result by 4. He then subtracts 2 and divides the number by 2. His final answer is 48. What number did Dennis start with?

Respuesta :

I’m pretty sure his starting number is 24! Just take the ending number and go through the problem and do the opposite function (:

The number that Dennis started with is 24

Further explanation

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

m → gradient of the line

( 0 , c ) → y - intercept

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

[tex]\large {m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

[tex]y - y_1 = m ( x - x_1 )[/tex]

Let us tackle the problem.

Let :

The number that Dennis started with is X

If he adds 0.5 to that number and then multiplies the new result by 4 , then:

[tex]( X + 0.5 ) \times 4[/tex]

If he then subtracts 2 and divides the number by 2 , then:

[tex]\frac{[ ( X + 0.5 ) \times 4 ] - 2}{2}[/tex]

If his final answer is 48 , then :

[tex]\frac{[ ( X + 0.5 ) \times 4 ] - 2}{2} = 48[/tex]

[tex][ ( X + 0.5 ) \times 4 ] - 2 = 48 \times 2[/tex]

[tex]( X + 0.5 ) \times 4 = 48 \times 2 + 2[/tex]

[tex]( X + 0.5 ) \times 4 = 96 + 2[/tex]

[tex]( X + 0.5 ) \times 4 = 98[/tex]

[tex]( X + 0.5 ) = \frac{98}{4}[/tex]

[tex]( X + 0.5 ) = \frac{49}{2}[/tex]

[tex]X = \frac{49}{2} - \frac{1}{2}[/tex]

[tex]X = \frac{48}{2}[/tex]

[tex]\large {\boxed {X = 24} }[/tex]

Learn more

  • Infinite Number of Solutions : https://brainly.com/question/5450548
  • System of Equations : https://brainly.com/question/1995493
  • System of Linear equations : https://brainly.com/question/3291576

Answer details

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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