Respuesta :
a) There are 36 possible outcomes.
b) The probability of a sum of 6 is 5/36.
c) She should roll a sum of 7 45 times.
d) She should roll a sum of 10 45 times.
Explanation
a) There are 6 outcomes for the first die and 6 outcomes for the second one. By the fundamental counting principle, there are 6*6 = 36 outcomes for both dice together.
b) The ways to get a sum of 6 are:
1&5; 2&4; 3&3; 4&2; 5&1. There are 5 possibilities out of a total of 36, or 5/36.
c) The ways to get a sum of 7 are:
1&6; 2&5; 3&4; 4&3; 5&2; 6&1. There are 6 out of 36, or 6/36=1/6. Since she is rolling the dice 150 times, she should get a sum of 6
1/6(150) = 150/6 = 45 times.
d) The ways to get a sum of 10 or more are:
4&6; 5&5; 6&4; 5&6; 6&5; 6&6
There are 6 ways out of 36, or 6/36 = 1/6. Since she is rolling the dice 150 times, she should get a sum of 10 or more
1/6(150) = 150/6 = 45 times.
b) The probability of a sum of 6 is 5/36.
c) She should roll a sum of 7 45 times.
d) She should roll a sum of 10 45 times.
Explanation
a) There are 6 outcomes for the first die and 6 outcomes for the second one. By the fundamental counting principle, there are 6*6 = 36 outcomes for both dice together.
b) The ways to get a sum of 6 are:
1&5; 2&4; 3&3; 4&2; 5&1. There are 5 possibilities out of a total of 36, or 5/36.
c) The ways to get a sum of 7 are:
1&6; 2&5; 3&4; 4&3; 5&2; 6&1. There are 6 out of 36, or 6/36=1/6. Since she is rolling the dice 150 times, she should get a sum of 6
1/6(150) = 150/6 = 45 times.
d) The ways to get a sum of 10 or more are:
4&6; 5&5; 6&4; 5&6; 6&5; 6&6
There are 6 ways out of 36, or 6/36 = 1/6. Since she is rolling the dice 150 times, she should get a sum of 10 or more
1/6(150) = 150/6 = 45 times.
Answer:
Step-by-step explanation:
a) When two number cubes are thrown possible outcomes are
[tex]6x6 =36[/tex]
b) Probability of tossing a sum of 6
Favourable outcomes = (1,5)(5,1)(2,4) (4,2) (3,3)
Hence probability =[tex]\frac{5}{36}[/tex]
c) For getting 7 favourable outcomes are
(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)
i.e one out of 6 chances.
Hence in 150 times Kamala should toss a sum of 7 --- [tex]\frac{1}{6} *150 =25[/tex]
d) Favourable outcomes for sum of 10 or greater
= (4,6) (6,4) (5,5) (5,6)(6,5)(6,6)
Probability for getting sum of 10 or greater = [tex]\frac{6}{36} =\frac{1}{6}[/tex]
No of times Kamila should toss 10 or greater
= [tex]\frac{150}{6} =25[/tex]
