GIVING AWAY 50 POINTS TO WHOEVER SHOWS LEGIT WORK!
The lengths of the sides of three squares are s, s + 1, and s + 2. If their total area is 365 cm squared (^2), find their total perimeter.
S= one length of square 1 S+1 = one length square 2 S+2= one length square 3
Our equation would be S^2+(S+1)^2+(S+2)^2=365
Idk if it would be called distribute but.. distribute S^2+S^2+2S+1+S^2+4S+4=365
Add like terms 3S^2+6S-360=0
Divide everything. By 3 S^2+2S-120=0
Factor (S-10)(S+12)=0
The two solutions are:
S-10=0 S=10
S+12=0 S=-12
Since a length can’t be a negative the only possible solution would be 10
Since a perimeter is all lengths added together we can multiply the length by four to get the perimeter
Square 1 10*4=40 Perimeter is 40cm
Square 2 S+1 =11 11*4=44 Perimeter is 44cm
Square 3 S+2=12 12*4=48 Perimeter is 48cm
Add all the perimeters together to get the total perimeter:
Total perimeter: 40+44+48=132
The total perimeter is 132cm
I hope this helps. Sorry if I messed up anything on here it was kinda hard to keep track of everything. Feel free to ask if you need anything cleared up :)