the balanced reaction between LiOH and HCl is as follows
LiOH + HCl ----> LiCl + H₂O
stoichiometry of LiOH to HCl is 1:1
number of moles of HCl reacted = concentration of HCl x volume
number of HCl moles = 0.3340 mol/L x (15.22 x 10⁻³ L) = 5.083 x 10⁻³ mol
according to molar ratio
number of HCl moles = number of LiOH moles
number of LiOH moles in 25.00 mL = 5.083 x 10⁻³ mol
therefore LiOH moles in 1 L = 5.083 x 10⁻³ mol / (25.00 x 10⁻³ L) = 0.2033 mol/L
molarity of LiOH - 0.2033 M
