The mass of the sheet of aluminium is the product between its density d and its volume V:
[tex]m=dV[/tex]
Re-arranging the equation, we can find the volume of the sheet:
[tex]V= \frac{m}{d}= \frac{3.716 g}{2.699 g/cm^3}= 1.377 cm^3[/tex]
Converted in millimeters,
[tex]V=1377 mm^3[/tex]
The area is
[tex]A=1.00 ft^2 [/tex]
Since [tex]1 ft = 0.305 m[/tex], this area corresponds to
[tex]A=1.00 ft^2 = (0.305 m)^2 = 0.093 m^2 = 0.093 \cdot 10^6 mm^2[/tex]
So we can now find the thickness of the sheet of aluminium:
[tex]t= \frac{V}{A}= \frac{1377 mm^2}{0.093 \cdot 10^6 mm^2}=0.015 mm [/tex]
