Respuesta :
The answers are 13.75 and 2.905.
1.) To get the total number of orange candies, we must multiply the given percentage to the size of the samples. Then, add the products.
Dynamite mints - 25 x 10% = 2.5
Holiday mints - 25 x 45% = 11.25
Total orange candies - 2.5 + 11.25 = 13.75
2.) To get the standard deviation, we will first find the standard deviation of each sample. Use this formula: standard deviation = √[np(1-p)] The variable n is the size of the sample while the p is the probability or percentage.
Dynamite mints - √[25 x 10% (1 - 10%)] = 1.5
Holiday mints - √[25 x 45% (1 - 45%)] = 2.4874...
After getting the standard deviations, we'll combine then using s^2 (x + y) = s^2(x) + s^2(y)
Standard deviation of orange candies = std of dynamite + std of holiday
Std = √(1.5^2 + 2.4874...^2) = √8.4375... = 2.9046 or 2.905
1.) To get the total number of orange candies, we must multiply the given percentage to the size of the samples. Then, add the products.
Dynamite mints - 25 x 10% = 2.5
Holiday mints - 25 x 45% = 11.25
Total orange candies - 2.5 + 11.25 = 13.75
2.) To get the standard deviation, we will first find the standard deviation of each sample. Use this formula: standard deviation = √[np(1-p)] The variable n is the size of the sample while the p is the probability or percentage.
Dynamite mints - √[25 x 10% (1 - 10%)] = 1.5
Holiday mints - √[25 x 45% (1 - 45%)] = 2.4874...
After getting the standard deviations, we'll combine then using s^2 (x + y) = s^2(x) + s^2(y)
Standard deviation of orange candies = std of dynamite + std of holiday
Std = √(1.5^2 + 2.4874...^2) = √8.4375... = 2.9046 or 2.905
The mean and standard deviation of the sample of orange sweets can be ibtaide using the binomial approximation relation. Hence, the mean and standard deviation are 13.75 and 2.905
Mean = np
- Sample size, n = 25
- Proportion, p
Dynamite mints :
- 25 x 0.1 = 2.5
Holiday mints:
- 25 x 0.45 = 11.25
Total orange candies = (2.5 + 11.25) = 13.75
2.)
Standard deviation, σ = √(npq)
- q = 1 - p
Dynamite mints :
√[25 x 0.1 × (1 - 0.1)] = 1.5
Holiday mints :
√[25 x 0.45 (1 - 0.45)] = 2.4874
Combined standard deviation : s²(x + y) = s²(x) + s²(y)
Std = √(1.5²2 + 2.4874²) = 2.905
Therefore, the mean and sample standard deviation are 13.75 and 2.905 respectively.
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