There is a missing part in the question. Found the complete text on internet:
"What is the largest size vehicle (kg) it can lift if the diameter of the output line is 28.0 cm? "
Solution
The diameter of the piston is 28.0 cm, this means its radius is 14.0 cm (half the diameter), so the area of the piston is
[tex]A=\pi r^2 = \pi (0.14 m)^2 =6.15 \cdot 10^{-2} m^2[/tex]
The maximum pressure of the lift is
[tex]p=18.0 atm = 1.82 \cdot 10^6 Pa[/tex]
Therefore the maximum force the piston can lift is
[tex]F=pA=(1.82 \cdot 10^6 Pa)(6.15 \cdot 10^{-2} m^2)=1.12 \cdot 10^5 N[/tex]
And the size (the mass) of the vehicle is
[tex]m= \frac{F}{g}= \frac{1.12 \cdot 10^5 Pa}{9.81 m/s^2} =1.14 \cdot 10^4 kg [/tex]