The gaseous product of a reaction is collected in a 25.0-l container at 27

c. the pressure in the container is 300.0 kpa and the gas has a mass of 96.0 g. how many moles of the gas are in the container?

Respuesta :

to find the number of moles of gas we can use the ideal gas law equation, we dont need to use the mass of gas given as we only have to find the number of moles 
PV = nRT 
P - pressure - 300.0 kPa 
V - volume - 25.0 x 10⁻³ m³
n - number of moles 
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature in Kelvin - 27 °C + 273 = 300 K
substituting these values in the equation 
300.0 kPa x 25.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 300 K 
n = 3.01 mol 
number of mols of gas - 3.01 mol

The number of moles of the gas in the system can be given by the ideal gas equation. There are 3.00 moles of gas in a 25.0 L container.

What is an ideal gas?

An ideal gas is a law that gives the relationship between the pressure, volume, moles, and temperature of the hypothetical gas conditions.

Given,

Pressure (P) = 300 kPa = 2.96 atm

Volume (V) = 25 L

Temperature (T) = 300.15 K

Gas constant (R) = 0.0821 atm.L/Kmol

Substituting values in the ideal gas equation, moles are calculated as:

PV = nRT

n = PV ÷ RT

= 2.96 × 25 ÷ 0.0821 × 300.15

= 74 ÷ 24.64

= 3.00 moles

Therefore, 3.00 moles of gas are present in a 25 L container.

Learn more about the ideal gas equation here:

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