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A 20.9 ml sample of 0.267 m koh solution required 29.1 ml of aqueous acetic acid solution in a titration experiment. calculate the molarity of the acetic acid solution. answer in units of m.

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kenmyna
The molarity of the acetic acid solution is calculated as below

calculate the moles of KOH used
moles =molarity x volume
= 20.9 x0.267 = 5.58 moles

write the reaction equation

KOH + CH3COOH = CH3COOK + H2O

since  the reacting ratio between KOH to CH3COOH is 1:1 the  moles of CH3COOH is also = 5.58  moles

molarity of CH3COOH = moles/volume

=5.58 /29.1 =0.192 M

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