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You can use a system of equations to answer this question.
1st: 2.20r + 3p = 700 is showing how to get the total cost.
2nd: r + p = 300 shows how many gallons were sold.
If we solve r + p = 300 for r, we can then solve the first equation in terms of r only.
r + p =300
p = 300 - r Use this in place of p in the first equation.
2.20r + 3p = 700
2.2r + 3(300 - r) = 700
2.2r + 900 - 3r = 700
-900 -900
2.2r - 3r = -200
-0.8r = -200
-0.8 -0.8
r = 250 gallons
There were 250 regular gallons sold and 50 premium gallons sold (300 - 250).
1st: 2.20r + 3p = 700 is showing how to get the total cost.
2nd: r + p = 300 shows how many gallons were sold.
If we solve r + p = 300 for r, we can then solve the first equation in terms of r only.
r + p =300
p = 300 - r Use this in place of p in the first equation.
2.20r + 3p = 700
2.2r + 3(300 - r) = 700
2.2r + 900 - 3r = 700
-900 -900
2.2r - 3r = -200
-0.8r = -200
-0.8 -0.8
r = 250 gallons
There were 250 regular gallons sold and 50 premium gallons sold (300 - 250).
The number of gallons of regular and premium gas sold will be 250 gallons and 50 gallons.
What is the solution to the equation?
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
A gas station sells regular gas for $2.20 per gallon and premium gas for $3.00 a gallon.
Let x be the number of gallons of regular gas and y be the number of gallons of premium gas.
At the end of a business day, 300 gallons of gas has been sold, and receipts totaled $700. Then the equation will be
x + y = 300
y = 300 - x ...1
2.2x + 3y = 700 ...2
From equations 1 and 2, then we have
2.2x + 3(300 - x) = 700
2.2x + 900 - 3x = 700
0.8x = 200
x = 250
Then the value of y will be
y = 300 - 250
y = 50
Then the number of gallons of regular and premium gas sold will be 250 gallons and 50 gallons.
More about the solution of the equation link is given below.
https://brainly.com/question/545403
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