(x-3)^2 + (y+5)^2 = 25
remove the ^2's from the left side:
(x-3) +(y+5) = sqrt(25)
(x-3) +(y+5) = 5
radius = 5
now solve for zero 's on the left side:
x-3 = 0 x = 3 (3-3=0)
y+5 = 0 y = -5 (-5 +5=0)
so center = (3,-5) and radius is 5
Answer is last one.
