Answer:
[tex](-9,-6)[/tex]
Step-by-step explanation:
We have been given an equation of a circle [tex](x+9)^2+(y+6)^2=225[/tex]. We are asked to find the coordinates of the center of the given circle.
We know that center-radius form of a circle is in format: [tex](x-h)^2+(y-k)^2=r^2[/tex], where,
[tex](h,k)=\text{Center of circle}[/tex],
[tex]r=\text{Radius of circle}[/tex]
Upon comparing our given equation with center-radius form of a circle we will get,
[tex](x-(-9))^2+(y-(-6))^2=15^2[/tex]
Therefore, the center of our given circle is at point [tex](-9,-6)[/tex].
