I would look at the minimum and maximum and see if any other the sets don't abide to it. Let's call the first set 1, second set 2, third set 3, fourth set 4.
They all have a minimum of 46 and maximum of 108. The median is 75 and since there's 10 numbers in each set, you would have to find the middle of two numbers.
First set:
Let's put them in order.
46, 66, 68, 68, 70, 70, 80, 82, 85, 108
The median of that set is 70, not 75.
Second Set:
Let's put them in order.
46, 66, 68, 68, 72, 78, 80, 80, 85, 108
Right away, I can tell the median of the set is 75. We should still check the other sets.
Third set:
Let's put them in order.
46, 66, 68, 72, 78, 80, 80, 82, 85, 108
Fourth set:
Let's put them in order.
46, 66, 68, 68, 72, 78, 80, 82, 85, 108
So, the fourth and second set both have a median of 75. We need to find their third quartile. On the graph, it is about 82 or 83.
Second Set's third quartile: 80
Fourth Set's third quartile: 82
So the box plot represents the last set of numbers.
