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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.

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Applicable equation:

R = [v^2* Sin 2Ф]/g, where R = horizontal range, Ф = angle, v = initial velocity, g=gravitational acceleration.

The missing value is the exact gravitational acceleration. Therefore,
g = [v^2*Sin 2Ф]/R = [13.9^2*Sin (2*25)]/15.1

At Ф = 35°;

R = [13.9^2*Sin (2*35)]/ {[13.9^2*Sin (2*25)]/15.1} = [15.1*Sin 70]/[Sin 50] ≈ 18.5 m

Therefore, if the ball was kicked at 35.0°, it would travel to 18.5 m before landing.
ttoporcer

Answer:

If the football is kicked at a 35.0º angle, it will travel 18.5 m before landing. This is farther than if it were kicked at a 25° angle.

Explanation:

what it says on edge