scribblesgalaxy
contestada

WILL MARK BRAINLIEST!!!
Use the drop downs to answer the following questions about the distance between the points (−5, 1) and (2, −1). What is the distance of the horizontal leg? What is the distance of the vertical leg? Use the Pythagorean theorem. What is the distance between the two points?

Respuesta :

The distance between the horizontal legs be the distance between the 'x' values '-5' and '2'. 2+5=7 (It is +5 because the distance between -5 and 0 is 5*) 
The distance between the horizontals is 7

Same with the vertical points, as the distance is 2. (1+1=2)

Considering that the pythagorean theorem is the a^2+b^2=c^2, and 'a' and 'b' are the sides, then you plug in '7' and '2', making the equation 7^2+2^2=c^2
49+4=c^2
53=c^2
c=sqrt(53)
Hope this helps.

The distance between the two points can be found by Pythagoras

theorem, given that their horizontal and vertical distance apart are known.

  • The distance of the horizontal leg is 7
  • The distance of the vertical leg is -2
  • The distance between the two points, c = [tex]\sqrt{53}[/tex]

Reasons:

The given points are; (-5, 1), and (2, -1)

The points expresses the following ordered pair;

(x₁, y₁) = (-5, 1)

(x₂, y₂) = (2, -1)

  • The distance of the horizontal leg is; a = |x₂ - x₁| = 2 - (-5) = 7
  • The distance of the vertical leg is; b = |y₂ - y₁| = -1 - 1 = -2

With Pythagoras theorem the direct distance between the points c can be

found using the formula [tex]c = \sqrt{a^2 + b^2}[/tex]

Where;

a = (x₂ - x₁)

b = (y₂ - y₁)

Therefore;

The distance between the two points by Pythagorean theorem is given as follows;

[tex]c = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]

Which gives;

[tex]c = \sqrt{\left (-1-1 \right )^{2}+\left (2-(-5) \right )^{2}} =\sqrt{4 + 49} =\sqrt{53}[/tex]

  • The distance between the two points, c = [tex]\sqrt{53}[/tex]

Learn more here:

https://brainly.com/question/13160273

Otras preguntas