Respuesta :

calculista
the correct question is
What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3

we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0

the answer is
x - 3y - 7 = 0

Answer:

Answer is III line

[tex]x - 3y - 7 = 0[/tex]

Step-by-step explanation:

Given that the line passes through (1,-2)

Hence when we substitute x=1 and y =-2 the equation should be satisfied

I equation

[tex]3x - y - 7 = 0\\3(1)-(-2) \neq 7\\x - 3y + 7 = 0\\1-3(-2)+7 = 14 \neq 0x - 3y - 7 = 0\\1-3(-2)-7 =0\\[/tex]

Hence third equation is the correct answer.

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