Carlos swam the perimeter of a rectangular pool seven times. If the length of the pool is 21 ft and the width of the pool is 9 ft, how many feet did Carlos swim?

Respuesta :

21+9+21+9=Perimeter of the pool = 60
And Carlos did this 7 times (x)...60 x 7 = 420



The total length did Carlos swim is 420 feet.

To find the perimeter.

What is rectangle?

A rectangle is a type of quadrilateral that has its parallel sides equal to each other and all the four vertices are equal to 90 degrees.

Given that:

Let the perimeter of rectangular swimming pool be x metres.

Then, its length =21 feet.

The width of the pool = 9 feet

The Perimeter of a rectangle =2(Length+Breadth)

According to the given condition, we have

Perimeter of a rectangle =2(Length+Breadth)

Perimeter of a rectangle=2(21+9)

Perimeter of a rectangle=2*30

Perimeter of a rectangle=60 feet

But, ​carlos swam the perimeter of a rectangular pool seven times.

Old perimeter=7*60=420  feet

Thus ,the total length did Carlos swim is 420 feet.

Learn more about rectangle here:

https://brainly.com/question/10064327

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