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The product of two consecutive integers is 156. what are the integers?" what type of equation should she create to solve this problem?

Respuesta :

calculista
let
x---------> the first integer
x+1------> the second consecutive integer

we know that
x*(x+1)=156-----> x²+x-156=0

using a graph tool-----> to resolve the second order equation
see the attached figure

the solution is 
x=12
x+1=13

the answer is
the numbers are
12 and 13
Ver imagen calculista

Answer:

12 and 13 or

- 13 and - 12

A quadratic equation r² + r - 156 = 0

Step-by-step explanation:

Let the first number be r, it means that the second will be r + 1.Given that the product of two consecutive integers is 156. we may interpret that to mean that

r(r + 1) = 156

r² + r - 156 = 0

r² + 13r - 12r -156 = 0

(r + 13)(r - 12) = 0

r = -13 0r 12

if r = -13, r + 1 = -12

If r = 12, r + 1 = 13