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Carbon disulfide is prepared industrially by reacting carbon with sulfur dioxide according to the above equation. if 5.9 moles of carbon react, how many moles of cs2 are produced?

Respuesta :

transitionstate
Answer:
             1.18 mol of CS₂

Solution:
The reaction is as follow,  

                            5 C + 2 SO₂     →    CS₂  +  4 CO

According to equation,,

             5 moles of Carbon on reaction produced  =  1 mole of CS₂
So,
                         5.9 moles of Carbon will produce  =  X g of CS₂

Solving for X,
                      X  =  (1 mol × 5.9 mol) ÷ 5 mol

                      X  =  1.18 mol of CS₂

Answer : The number of moles of carbon sulfide produced are, 1.18 moles.

Explanation : Given,

Moles of carbon = 5.9 moles

The balanced chemical reaction is:

[tex]5C+2SO_2\rightarrow CS_2+4CO[/tex]

From the balanced chemical reaction we conclude that,

As, 5 moles of carbon react to give 1 mole of carbon sulfide

So, 5.9 moles of carbon react to give [tex]\frac{5.9}{5}=1.18[/tex] mole of carbon sulfide

Thus, the number of moles of carbon sulfide produced are, 1.18 moles.

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