Respuesta :

carlosego
To solve the problem given in the figure attached, you must apply the proccedure shown below:

 1. You have the following expression given in the problem:

 x^19 = y

 2. By definition, you have:

 logb(x)=y
 b^y=x

 3. Therefore, you have:

 
 x^19 = y
 logx(y)=19

 4. Then, as you can see, the answer is:  logx(y)=19

 
aencabo
log properties or log transformation is;

b ^ x = a , then to solve for the exponent x, log b a = x or read as log a base b = x.

 x^19 = y

x = b
a = y
x = 19

log x y = 19 or log y base x = 19

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