jaredisshmexy
jaredisshmexy
11-05-2018
Mathematics
contestada
Please help with geometry
Respuesta :
gmany
gmany
11-05-2018
Use:[tex]A_\Delta=\dfrac{1}{2}ab\sin\alpha[/tex]
[tex]a=503ft=\dfrac{503}{3}yd\approx168yd\\\\b=516ft=\dfrac{516}{3}yd=172yd\\\\\sin38^o\approx0.616[/tex]
Substitute:
[tex]A_\Delta=\dfrac{1}{2}\cdot168\cdot172\cdot0.616\approx8,877yd^2[/tex]
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