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The electric field that is 0.25m from a small sphere is 450n/c toward the sphere.
a. Is the charge positive or negative? Why?
b. What is the magnitude of the charge on the sphere?

Respuesta :

its b bc its the volume of the sphere 

PART 1)

A small sphere is considered to be a point charge

So here if electric field is indicating the position of charge itself or it is towards the charge then it must be a negative charge on the sphere

PART 2)

Electric field due to a point charge is given by

[tex]E = \frac{KQ}{r^2}[/tex]

here

[tex]k = 9 * 10^9[/tex]

[tex]Q = charge[/tex]

[tex]r[/tex] = distance of charge from the point where field strength is required

= 0.25 m

[tex]E = 450 N/c[/tex]

now from the above equation we can say

[tex]450 = \frac{9*10^9 * Q}{0.25^2}[/tex]

[tex]Q = 3.125 * 10^{-9} C[/tex]

So magnitude of charge is 3.125 nC on the small sphere

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