Respuesta :

carlosego
The lateral area is:
 Al = (4) * (1/2) * (b) * (h)
 Where,
 b: base of the triangle
 h: height of the triangle
 Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2))
 Al = (4) * (root (1 + 9))
 Al = 4raiz (10) units ^ 2
 Answer:
 Al = 4raiz (10) units ^ 2
aencabo
 The answer would be Al = 4raiz (10) units ^ 2Formula:
Al = (4) * (1/2) * (b) * (h)
 Where, b= base of the triangle h=height of the triangle Al = (4) * (1/2) * (2) * (root ((1) ^ 2 + (3) ^ 2)) Al = (4) * (root (1 + 9)) Al = 4raiz (10) units ^ 2 

Otras preguntas