Given function is h(x) = [tex] x^{2} [/tex]+3x−18
To find the zero of the given function make h(x) = 0 and factor the given quadratic equation and find the value of x
[tex] x^{2} [/tex]+3x−18 = 0
(x + 6)(x-3) = 0
x + 6 = 0
Add - 6 on both sides
x + 6 - 6 = 0 - 6
x = -6
x - 3 = 0
Add 3 on both sides
x - 3 + 3 = 0 + 3
x =3
So zeros of the the given function are - 6 and 3
