Following reaction takes place between LiOH and HNO3
LiOH + HNO3 → LiNO3 + H2O
Thus, 1 mole of LiOH reacts with 1 mole of HNO3 to form 1 mole of LiNO3.
Now,
Number of millimoles of LiOH consumed = 36.90 X 0.100 = 3.690
∴Number of millimoles of HNO3 present = 3.690
Now, Molarity of HNO3 = [tex] \frac{\text{number of millimoles of HNO3}}{\text{volume of solution (ml)}} [/tex]
= [tex] \frac{3.690}{50} [/tex] = 0.0738 M
Thus, molarity of the HNO3 solution is 0.0738 M
