Respuesta :
For x > 1 and x < -1, we can multiply by the product of the denominators to get
2(x+1) > 7(x-1)
9 > 5x
x < 9/5
For -1 < x < 1, we can do the same, but we must reverse the sense of the inequality.
2(x+1) < 7(x-1)
9 < 5x
x > 1.8
A graph confirms the solution is
-∞ < x < -1 ∪ 1 < x < 1.8
2(x+1) > 7(x-1)
9 > 5x
x < 9/5
For -1 < x < 1, we can do the same, but we must reverse the sense of the inequality.
2(x+1) < 7(x-1)
9 < 5x
x > 1.8
A graph confirms the solution is
-∞ < x < -1 ∪ 1 < x < 1.8
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[tex] \dfrac{2}{x - 1} > \dfrac{7}{x + 1} \\ \\ \dfrac{2}{x - 1} - \dfrac{7}{x + 1} > 0 \\ \\ \frac{2(x + 1) - 7(x - 1)}{ {x}^{2} - 1} > 0 \\ \\ 2(x + 1) - 7(x - 1) > 0 \\ \\ 2x + 2 - 7x + 7 > 0 \\ \\ 5x < 9 \: \: \\ \\ || \: \: \: x < 1.8 \: \: || \: \: \: \: \: \: \: Ans.[/tex]
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