Respuesta :
If this is for E2020 the answer is
D)No, his value of should be positive because an even exponent indicates a positive value.
thats why it was wrong
D)No, his value of should be positive because an even exponent indicates a positive value.
thats why it was wrong
Answer with explanation:
We have to evaluate the expression for, x=3 and y= -4 .The expression is
[tex]\rightarrow x \times y^{-2} \times 3 \times x^2 \times y^{-4}\\\\ \rightarrow 3 x^{1+2} \times y^{-2-4}\\\\ \rightarrow 3 x^{3} \times y^{-6}\\\\=3 (3)^3 \times (-4)^{-6}\\\\=\frac{3^4}{4^6}\\\\ \text{used}x^a \times x^b=x^{a+b}\\\\x^{-a}=\frac{1}{x^a}[/tex]
