Respuesta :
Answer: C) 2
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Work Shown:
Let x be some integer from the set {..., -3, -2, -1, 0, 1, 2, 3, ...}.
The multiplicative inverse of x is a number y such that x*y = 1.
Since we want x and y to be the same, this means y = x
Use substitution to go from
x*y = 1
to
x*x = 1
Basically I've replaced y with x
Now solve for x
x*x = 1
x^2 = 1
x = +-sqrt(1)
x = 1 or x = -1
There are 2 values of x where they are their own multiplicative inverse
1*1 = 1
(-1)*(-1) = 1
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Work Shown:
Let x be some integer from the set {..., -3, -2, -1, 0, 1, 2, 3, ...}.
The multiplicative inverse of x is a number y such that x*y = 1.
Since we want x and y to be the same, this means y = x
Use substitution to go from
x*y = 1
to
x*x = 1
Basically I've replaced y with x
Now solve for x
x*x = 1
x^2 = 1
x = +-sqrt(1)
x = 1 or x = -1
There are 2 values of x where they are their own multiplicative inverse
1*1 = 1
(-1)*(-1) = 1
Nuber of integers are their own multiplicative inverses is option C 2.
What is multiplicative inverse?
The multiplicative inverse of various is described as more than a few that after extended with the aid of the authentic variety offers the product as 1. The multiplicative inverse
Let x be some integer from the set {. -3, -2, -1, 0, 1, 2, 3, ...}.
The multiplicative inverse of x is a number y such that x*y = 1.
Since we want x and y to be the same, this means y = x
Use substitution to go from
x*y = 1 to x*x = 1
Basically I've replaced y with x
Now solving for x,
x*x = 1
x^2 = 1
x =±[tex]\sqrt{1}[/tex]
x = 1 or x = -1
There are 2 values of x where they are their own multiplicative inverse
1*1 = 1
(-1)*(-1) = 1
Hence integers are their own multiplicative inverses of 2.
Learn more about multiplicative inverse here:-https://brainly.com/question/1682347
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