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altavistard
The wording of your question suggests that there were answer choices.  Mind sharing them?

The system   y=-2x^2 y=x-2 would be best written as:

y=-2x^2 
y=x-2                  If you subst. x-2 for y in the first equation, you'll get:
                           x-2 = -2x^2,   or 2x^2 + x - 2 = 0.
                           

Answer:

Step-by-step explanation:

[tex]y= -2x^{2}\\and\\y =x-2[/tex]

substituting y =x-2 in equation first we get

[tex]y= -2x^{2}[/tex]

[tex](x-2)= -2x^{2}[/tex]

[tex]2x^{2}+x-2=0[/tex]

solving it using quadratic formula we get

x =-1.281 and corresponding y =-3.281

for x =0.781 we have y =-1.219

more over we can graph both given and find the points of intersection from it.

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