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Submarine A is positioned at –1,100 feet in relation to sea level. Submarine B is positioned at –800 feet in relation to sea level. Each submarine needs to be 200 feet below sea level in 30 minutes. Which compares the speeds at which each submarine needs to travel?

I will give branliest to the first answer that explains why their answer is correct

Respuesta :

mreijepatmat
Distance of sub A to reach (-200 ft) = -1,100 - (-200) = |900| feet
Distance of sub B to reach (-200 ft) = -600 - (-200) = |400| feet
Speed = Distance/time:
Speed sub A = 900/0.5 = 1800 ft/hour
Speed sub B = 400/0.5 = 900 ft/hour

zfishkind8220

Answer:

43.33

33.33

Step-by-step explanation:

Speed = distance/time

Now, submarine A is presently 1100ft away from sea level and still needs to cover a distance of 200ft below sea level. The total distance it needs to cover is 1100 + 200 = 1300ft

Submarine B is at a distance of 800ft above sea level and still needs to go 200ft below. Total distance needed to be covered is 800 + 200 = 1000ft.

The speed of submarine A = 1300/30 = 43.33ft/min

The speed of submarine B = 1000/30 = 33.33ft/min