There are 3 green balls, 5 red balls and 2 blue balls in a box. One ball is randomly drawn, replaced and then another ball is drawn.
What is the probability of getting a green ball than a blue ball?
The probability of getting a green ball at the first drawn p₁ = [tex] \dfrac{green}{total}[/tex] p₁ = [tex] \dfrac{3}{3+5+2} [/tex] p₁ = [tex] \dfrac{3}{10} [/tex]
The green ball is replaced, that means the total ball is still 10. The probability of getting a blue ball at the second drawn p₂ = [tex] \dfrac{blue}{total}[/tex] p₂ = [tex] \dfrac{2}{10} [/tex] p₂ = [tex] \dfrac{1}{5} [/tex]
The probability of both event p = p₁ × p₂ p = [tex]\dfrac{3}{10} \times \dfrac{1}{5}[/tex] p = [tex] \dfrac{3}{50} [/tex]
