Answer: [tex]\dfrac{2}{3}[/tex]
Step-by-step explanation:
Given : The total number of regions in the spinner = 21
The outcomes for even number =2,4,6,8,10,12,14,16,18,20
The outcomes for multiple of 3 = 3,6,9,12,15,18,21
The number of outcomes of getting an even number or a multiple of 3 = 14
Then, the probability that the spinner will stop on an even number or a multiple of 3 will be :-
[tex]\dfrac{14}{21}=\dfrac{2}{3}[/tex]
Hence, the probability that the spinner will stop on an even number or a multiple of 3 is [tex]\dfrac{2}{3}[/tex]
