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Abby must create a three-character password for her computer the is two different, upper-case letters followed by one digit. if she only is willing to use the letters in her first name and a digit in the current year(2011), how many possible passwords can she create? one possible password to include s YB1

Respuesta :

The number of different permutations  of 2 letters from the name Abby 
= 3P2 =  3! / 3-2! = 3*2*1 = 6
Number of different  digits in 2011 = 3

Number of possible passwords = 6*3 = 18 (answer).

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