Answer:
The factored form is: (x-2)(x-4) = 0
Explanation:
To factor an expression, we need to get its solutions.
The standard form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
x² - 6x + 8 = 0
By comparison:
a = 1
b = -6
c = 8
Now, to get the roots, we will substitute with the values of a, b and c in the quadratic formula shown in the attached image.
This will give us:
either x = [tex] \frac{6+ \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 4[/tex]
This means that the first factor is (x-4)
or x = [tex] \frac{6- \sqrt{(-6)^2-4(1)(8)} }{2(1)} = 2[/tex]
This means that the second factor is (x-2)
Based on the above, the factored form would be:
(x-4)(x-2) = 0
Hope this helps :)
