Select the precipitate that forms when aqueous ammonium sulfide reacts with aqueous copper(ii) nitrate. refer to the solubility rules.

Precipitate is defined as the insoluble salt that is formed when two different solutions are mixed together. It settles down at the bottom of the flask after some time.

The balanced chemical equation for the reaction of ammonium sulfide and copper (II) nitrate follows:

[tex](NH_4)_2S(aq.)+Cu(NO_3)_2(aq.)\rightarrow CuS(s)+2NH_4NO_3(aq.)[/tex]

By Stoichiometry of the reaction:

1 mole of aqueous solution of ammonium sulfide reacts with 1 mole of aqueous solution of copper (II) nitrate to produce 1 mole of solid copper (II) sulfide and 2 moles of aqueous solution of ammonium nitrate.

Hence, the precipitate formed is copper (II) sulfide.

pstnonsonjoku pstnonsonjoku · Answer 2 · 2022-03-03T11:39:17+01:00

All sulfide salts are insoluble except those of ammonium and the alkali metals.

The solubility rules give us an idea of what compound will dissolve in water ad which ones would not. It serves a sort of a solubility guide.

Now consider the reaction; (NH4)2S(aq) + Cu(NO3)2 (aq) -----> CuS(s) + 2NH4NO3(aq). We must note that all sulfide salts are insoluble except those of ammonium and the alkali metals.

Learn more about solubility rules: https://brainly.com/question/12978582