Respuesta :

McChuck
The conversion factor for volume at STP is [tex]\frac {1mol}{22.4L}[/tex] or [tex]\frac {22.4L}{1mol}[/tex]. Since we want volume, we would use [tex]\frac {22.4L}{1mol}[/tex]. We conclude with the following calculations:

[tex]0.435mol H_{2} * \frac {22.4LH_{2}}{1molH_{2}} = 9.744L[/tex]

The answer is 9.744L H2

Answer: The volume occupied by 0.435 moles of [tex]H_2[/tex] will be 9.7 Liters.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

Thus if 1 mole of [tex]H_2[/tex]  occupies 22.4 L at STP

0.435 moles of [tex]H_2[/tex]  occupies=[tex]\frac{22.4}{1}\times 0.435=9.8L[/tex] L at STP

The volume occupied by 0.435 moles of [tex]H_2[/tex] will be 9.7 Liters.

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