Respuesta :
Answer is: new pressure is 775 mmHg.
Boyle's law: the product of the pressure and volume of of an ideal gas in a closed system is always constant.
p₁V₁ = p₂V₂.
p₁ = 310 mmHg; pressure of gas.
V₁ = 185 ml; volume of gas.
V₂ = 74.0 ml; new volume of gas.
p₂ = p₁V₁ ÷ V₂; new pressure of gas.
p₂ = 310 mmHg · 185 ml ÷ 74 ml.
p₂ = 775 mmHg.
Boyle's law: the product of the pressure and volume of of an ideal gas in a closed system is always constant.
p₁V₁ = p₂V₂.
p₁ = 310 mmHg; pressure of gas.
V₁ = 185 ml; volume of gas.
V₂ = 74.0 ml; new volume of gas.
p₂ = p₁V₁ ÷ V₂; new pressure of gas.
p₂ = 310 mmHg · 185 ml ÷ 74 ml.
p₂ = 775 mmHg.
Hello!
Data:
Vo (initial volume) = 185 mL
V (final volume) = 74 mL
Po (initial pressure) = 310 mmHg
P (final pressure) = ? (in mmHg)
We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the formula, we have:
[tex]P_0*V_0 = P*V[/tex]
[tex]310*185 = 74*P[/tex]
[tex]57350 = 74P[/tex]
[tex]74P = 57350[/tex]
[tex]P = \dfrac{57350}{74} [/tex]
[tex]\boxed{\boxed{P = 775\:mmHg}}\end{array}}\qquad\checkmark[/tex]
I hope this helps. =)
Data:
Vo (initial volume) = 185 mL
V (final volume) = 74 mL
Po (initial pressure) = 310 mmHg
P (final pressure) = ? (in mmHg)
We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the formula, we have:
[tex]P_0*V_0 = P*V[/tex]
[tex]310*185 = 74*P[/tex]
[tex]57350 = 74P[/tex]
[tex]74P = 57350[/tex]
[tex]P = \dfrac{57350}{74} [/tex]
[tex]\boxed{\boxed{P = 775\:mmHg}}\end{array}}\qquad\checkmark[/tex]
I hope this helps. =)