What mass, in grams, of oxygen gas (O2) is contained in a 10.5-liter tank at 27.3 degrees Celsius and 1.83 atmospheres? Show all of the work used to solve this problem.
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to find the mass of O₂ in the container we can use the ideal gas law equation PV = nRT where P - pressure - 1.83 atm V - volume - 10.5 L n - number of moles of O₂ R - universal gas constant - 0.0821 L.atm/mol.K T - temperature in kelvin - 27.3 °C + 273 = 300.3 K substituting the values in the equation 1.83 atm x 10.5 L = n x 0.0821 L.atm/mol.K x 300.3 K n = 0.779 mol the number of moles of O₂ are 0.779 mol mass of O₂ = number of moles x molar mass mass of O₂ = 0.779 mol x 32 g/mol = 24.9 g therefore mass of O₂ in the container is 24.9 g
