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Find the perimeter of the image below: Figure PQRST is shown. P is at negative 2, 11. Q is at negative 4, 5. R is at 2, 0. S is at 1, 7. T is at 8, 7. 37 units 38 units 39 units 40 units

Respuesta :

carlosego
For this case, the first thing to do is to graph the ordered pairs and join the points.
 Then, we use the formula of distance between points:
 [tex]d = \sqrt{(x2-x1)^2 + (y2-y1)^2} [/tex]
 We have then:
 
 For TP:
 [tex]TP = \sqrt{(-2-8)^2 + (11-7)^2} [/tex]
 [tex]TP = 10.77032961 [/tex]

 For PQ:
 [tex]PQ = \sqrt{(-4-(-2))^2 + (5-11)^2} [/tex]
 [tex]PQ = 6.32455532 [/tex]
 
 For QR:
 [tex]QR = \sqrt{(2-(-4))^2 + (0-5)^2} [/tex]
 [tex]QR =  7.81024968 [/tex]

 For RS:
 [tex]RS = \sqrt{(1-2)^2 + (7-0)^2} [/tex]
 [tex]RS =  7.07106781 [/tex]

 For ST:
 [tex]ST = \sqrt{(8-1)^2 + (7-7)^2} [/tex]
 [tex]ST =  7 [/tex]

 Then, the perimeter of the figure is the sum of the lengths:
 [tex]P = 10.7703296 + 6.32455532 + 7.81024968 + 7.07106781 + 7 P = 38.97[/tex]
 Rounding off we have:
 [tex]P = 39 [/tex]

 Answer:
 the perimeter of the image is:
 39 units
Ver imagen carlosego

Answer:

39 units

Step-by-step explanation:

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