A set of score has a mean of μ = 63 and a standard deviation of σ = 8. if these scores are standardized so that the new distribution has μ = 50 and σ = 10, what new value would be obtained for a score of x = 59 from the original distribution?

Respuesta :

The z-score of 59 in the original distribution is

z = (59 - 63)/8 = -1/2


The corresponding x-score in the new distribution is

-1/2 = (x - 50)/10

-5 = x - 50

45 = x


The new value of 45 would be obtained for a score of 59 from the original distribution.