Respuesta :
So for this, this can be written into the equation [tex]y=50x+35[/tex] (x = number of months, y = total cost).
To solve this problem, we need to plug in 1325 into the y-variable and solve from there.
[tex]1325=50x+35[/tex]
Subtract 35 on each side to get [tex]1290=50x[/tex]
Then just divide by 50 on each side, and your answer should be [tex]25.8=x[/tex]
And because we cannot go past budget, we will have to round down to 25. In context, the maximum amount of months Abbey can do is 25 months.
To solve this problem, we need to plug in 1325 into the y-variable and solve from there.
[tex]1325=50x+35[/tex]
Subtract 35 on each side to get [tex]1290=50x[/tex]
Then just divide by 50 on each side, and your answer should be [tex]25.8=x[/tex]
And because we cannot go past budget, we will have to round down to 25. In context, the maximum amount of months Abbey can do is 25 months.
The first thing we are going to do for this case is define variables.
We have then:
x: number of months
y: total cost
We now write the linear function that models the problem:
[tex]y = 50x + 35 [/tex]
The maximum number of months occurs when savings are reached.
Therefore, substituting y = 1325 we have:
[tex]1325 = 50x + 35 [/tex]
From here, we clear x:
[tex]50x = 1325-35 50x = 1290 x = 1290/50 x = 25.8[/tex]
Rounding the nearest whole before the next number:
[tex]x = 25 [/tex]
Answer:
The maximum number of months for which Abbey can learn yoga with her savings is:
[tex]x = 25[/tex]
We have then:
x: number of months
y: total cost
We now write the linear function that models the problem:
[tex]y = 50x + 35 [/tex]
The maximum number of months occurs when savings are reached.
Therefore, substituting y = 1325 we have:
[tex]1325 = 50x + 35 [/tex]
From here, we clear x:
[tex]50x = 1325-35 50x = 1290 x = 1290/50 x = 25.8[/tex]
Rounding the nearest whole before the next number:
[tex]x = 25 [/tex]
Answer:
The maximum number of months for which Abbey can learn yoga with her savings is:
[tex]x = 25[/tex]