The weight of a person on or above the surface of the earth varies inversely as the square of the distance the person is from the center of the earth. A particular person weighs 179 pounds on the surface of the earth and the radius of the earth is 3900 miles. Determine the equation that relates weight, W, to the distance from the center of the earth, d, for this person.

please help Im being timed

Respuesta :

To solve this problem you must apply the proccedure shown below:

1. You have the following information given in the problem: "...the weight of a person on or above the surface of the earth varies inversely as the square of the distance the person is from the center of the earth". Therefore, you can write the following equation, where [tex] W [/tex] is the weight, [tex] d [/tex] is the distance from the center of the earth and [tex] k [/tex] is the constant of proportionality:

[tex] W=\frac{k}{d^{2}} [/tex]

2. You can find the value of the constant of proportinality, by using the weight of the person and the distance given in the problem, and solve for the constant, as following:

[tex] 179=\frac{k}{(3,900)^{2}} \\ k=(2.72)(10^{9}) [/tex]

Therefore, the answer is: [tex] W=\frac{(2.72)(10^{9})}{d^{2}} [/tex]

GWay

Answer:

The answer is C

Step-by-step explanation: