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The decay of 601 mg of an isotope is described by the function A(t)= 601e-0.019t, where t is time in years. Find the amount left after 34 years. Round your answer to the nearest mg. Show all of your work for full credit. (5 points)

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sqdancefan

Put 34 where t is, then evaluate.

... A(34) = 601·e^(-0.019·34) = 601·e^-0.646

... = 601·0.524138

... ≈ 315


The amount left after 34 years is 315 mg.

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