A spinner has 12 equal sectors with different letters for each sector, as shown below: A spinner with 12 equal sectors is shown. The sectors are labeled B, Y, G, C, P, O, V, M, A, D, E, and R. Hamlet spins the spinner 5 times, and it stops at the letter "B" 4 times. If he spins the spinner a 10th time, what is the theoretical probability that this time it will stop at the letter 'B'?

Respuesta :

The theoretical probability of an event is not affected by previous outcomes. The only then that matters is the math.
(Sidebar: Forgetting or ignoring this is a big part of gambling addiction, just because your number hasn't come up in a while in no way means you are 'due' for a win.)

For any probability:
[tex]P_{desired}=\frac{N_{desired}}{N_{total}}[/tex]

In this case:
[tex]P_{B}=\frac{N_{B}}{N_{B}}[/tex]
[tex]P_{B}=\frac{1}{12}[/tex]

This is the same as it would always be. There is always 1/12 chance of a [tex]B[/tex]. What happened before doesn't matter. 

The theoretical probability that this time it will stop at the letter 'B' will be 1 / 12

Probability

Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur, or how likely it is that a proposition is true.

What are steps to solve this problem?

The steps are as follow:

  • Given that spinner has total 12 equal sector, so that total outcome will be 12
  • Since B is labeled only one times the probable outcome will be 1
  • So the probability is given by following formula:

P = Probable outcome / Total outcome

P = 1 / 12

So the theoretical probability that this time it will stop at the letter 'B' will be 1/12

Learn more about probability here:

https://brainly.com/question/251701

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