AC = 2 (x-3)
BD = x + 5
For this case, the length of the diagonals is the same.
Therefore we have:
AC = BD
Substituting values we have:
2 (x-3) = x + 5
From here, we clear the value of x.
We have then:
2x-6 = x + 5
2x - x = 5 + 6
x = 11
Finally, we substitute the value of x in any of the equations:
11 + 5 = 16
Answer:
the length of each diagonal is:
16 units
