The value of an antique plate after x years can be modeled by f(x) = 18(1.05)x. Which graph can be used to approximate the number of years it will take for the plate’s value to be $30?
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we have that
[tex] f(x)=18*(1.05^{x} ) [/tex]
using a graph tool
see the attached figure N 1
for f(x)=$30
the number of years x is equal
x=10.47 years
the answer in the attached figure N 2
Answer:
Option A
Step-by-step explanation:
Given : The value of an antique plate after x years can be modeled by
[tex]f(x) = 18(1.05)^x[/tex]
To find : Which graph can be used to approximate the number of years it will take for the plate’s value to be $30.
Solution: First we find the value of x at y=30
[tex]f(x) = 18(1.05)^x[/tex]
[tex]30 = 18(1.05)^x[/tex]
[tex]\frac{30}{18}=(1.05)^x[/tex]
[tex]1.6666=(1.05)^x[/tex]
Taking log both side and apply property [tex]logx^a=alogx[/tex]
[tex]log(1.6666)=xlog(1.05)[/tex]
[tex]0.221848749616=x0.0211892990699[/tex]
[tex]\frac{0.221848749616}{0.0211892990699}=x[/tex]
[tex]x=10.4698484308[/tex]
Therefore, from the given graph where the value (x,y)=(10.47,30) lie and the curve from (0,18) to (10.47,30) is the solution of the answer.
Hence, option A is correct (also correct graph is attached)