I'm not sure how to solve this
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we know that sum of interior angles of a triangle is 180.
we have given three angles as A,B and C .
[tex] A=x-2,B=4x+1,C=4x+1 [/tex].
we need to find x and then plug the values of x in A,B and C.[tex] x-2+4x+1+4x+1=180. [/tex]
[tex] 9x=180,x=20 [/tex]..
[tex] A=20-2=18,B=4(20)+1=81,C=4(20)+1=81. [/tex]